This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
0011000010101012 = 001 100 001 010 101 = 001(=1) 100(=4) 001(=1) 010(=2) 101(=5) = 141258
answer: 11000010101012 = 141258
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙214+0∙213+1∙212+1∙211+0∙210+0∙29+0∙28+0∙27+1∙26+0∙25+1∙24+0∙23+1∙22+0∙21+1∙20 = 0∙16384+0∙8192+1∙4096+1∙2048+0∙1024+0∙512+0∙256+0∙128+1∙64+0∙32+1∙16+0∙8+1∙4+0∙2+1∙1 = 0+0+4096+2048+0+0+0+0+64+0+16+0+4+0+1 = 622910
got It: 0011000010101012 =622910
Translate the number 622910 в octal like this:
the Integer part of the number is divided by the base of the new number system:
6229 | 8 | | | | |
-6224 | 778 | 8 | | | |
5 | -776 | 97 | 8 | | |
| 2 | -96 | 12 | 8 | |
| | 1 | -8 | 1 | |
| | | 4 | | |
|
the result of the conversion was:
622910 = 141258
answer: 11000010101012 = 141258