This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
15∙164+12∙163+3∙162+10∙161+11∙160 = 15∙65536+12∙4096+3∙256+10∙16+11∙1 = 983040+49152+768+160+11 = 103313110
got It: FC3AB16 =103313110
Translate the number 103313110 в octal like this:
the Integer part of the number is divided by the base of the new number system:
1033131 | 8 | | | | | | |
-1033128 | 129141 | 8 | | | | | |
3 | -129136 | 16142 | 8 | | | | |
| 5 | -16136 | 2017 | 8 | | | |
| | 6 | -2016 | 252 | 8 | | |
| | | 1 | -248 | 31 | 8 | |
| | | | 4 | -24 | 3 | |
| | | | | 7 | | |
|
the result of the conversion was:
103313110 = 37416538
answer: FC3AB16 = 37416538
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
FC3AB16 = F C 3 A B = F(=1111) C(=1100) 3(=0011) A(=1010) B(=1011) = 111111000011101010112
answer: FC3AB16 = 111111000011101010112
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
0111111000011101010112 = 011 111 100 001 110 101 011 = 011(=3) 111(=7) 100(=4) 001(=1) 110(=6) 101(=5) 011(=3) = 37416538
answer: FC3AB16 = 37416538