This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the right
let\'s make a direct translation from binary to post-binary like this:
101011.1102 = 101 011. 110 = 101(=5) 011(=3). 110(=6) = 53.68
answer: 101011.112 = 53.68
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
1∙25+0∙24+1∙23+0∙22+1∙21+1∙20+1∙2-1+1∙2-2+0∙2-3 = 1∙32+0∙16+1∙8+0∙4+1∙2+1∙1+1∙0.5+1∙0.25+0∙0.125 = 32+0+8+0+2+1+0.5+0.25+0 = 43.7510
got It: 101011.1102 =43.7510
Translate the number 43.7510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
43 | 8 | |
-40 | 5 | |
3 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 75*8 |
6 | .0*8 |
the result of the conversion was:
43.7510 = 53.68
answer: 101011.112 = 53.68