This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
let\'s do a direct translation from binary to hexadecimal like this:
0001110001012 = 0001 1100 0101 = 0001(=1) 1100(=C) 0101(=5) = 1C516
answer: 0001110001012 = 1C516
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙211+0∙210+0∙29+1∙28+1∙27+1∙26+0∙25+0∙24+0∙23+1∙22+0∙21+1∙20 = 0∙2048+0∙1024+0∙512+1∙256+1∙128+1∙64+0∙32+0∙16+0∙8+1∙4+0∙2+1∙1 = 0+0+0+256+128+64+0+0+0+4+0+1 = 45310
got It: 0001110001012 =45310
Translate the number 45310 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
453 | 16 | | |
-448 | 28 | 16 | |
5 | -16 | 1 | |
| C | | |
|
the result of the conversion was:
45310 = 1C516
answer: 0001110001012 = 1C516