This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from octal to binary like this:
1101.01018 = 1 1 0 1. 0 1 0 1 = 1(=001) 1(=001) 0(=000) 1(=001). 0(=000) 1(=001) 0(=000) 1(=001) = 001001000001.0000010000012
answer: 1101.01018 = 1001000001.0000010000012
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
1∙83+1∙82+0∙81+1∙80+0∙8-1+1∙8-2+0∙8-3+1∙8-4 = 1∙512+1∙64+0∙8+1∙1+0∙0.125+1∙0.015625+0∙0.001953125+1∙0.000244140625 = 512+64+0+1+0+0.015625+0+0.000244140625 = 577.01586914062510
got It: 1101.01018 =577.01586914062510
Translate the number 577.01586914062510 в binary like this:
the Integer part of the number is divided by the base of the new number system:
577 | 2 | | | | | | | | | |
-576 | 288 | 2 | | | | | | | | |
1 | -288 | 144 | 2 | | | | | | | |
| 0 | -144 | 72 | 2 | | | | | | |
| | 0 | -72 | 36 | 2 | | | | | |
| | | 0 | -36 | 18 | 2 | | | | |
| | | | 0 | -18 | 9 | 2 | | | |
| | | | | 0 | -8 | 4 | 2 | | |
| | | | | | 1 | -4 | 2 | 2 | |
| | | | | | | 0 | -2 | 1 | |
| | | | | | | | 0 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 015869140625*2 |
0 | .03174*2 |
0 | .06348*2 |
0 | .12695*2 |
0 | .25391*2 |
0 | .50781*2 |
1 | .01563*2 |
0 | .03125*2 |
0 | .0625*2 |
0 | .125*2 |
0 | .25*2 |
the result of the conversion was:
577.01586914062510 = 1001000001.00000100002
answer: 1101.01018 = 1001000001.00000100002