This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s translate to decimal like this:
6∙82+7∙81+3∙80+6∙8-1 = 6∙64+7∙8+3∙1+6∙0.125 = 384+56+3+0.75 = 443.7510
got It: 673.68 =443.7510
Translate the number 443.7510 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
443 | 16 | | |
-432 | 27 | 16 | |
B | -16 | 1 | |
| B | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 75*16 |
C | .0*16 |
the result of the conversion was:
443.7510 = 1BB.C16
answer: 673.68 = 1BB.C16
now let\'s make the transfer using the decimal system.
let\'s do a direct translation from octal to binary like this:
673.68 = 6 7 3. 6 = 6(=110) 7(=111) 3(=011). 6(=110) = 110111011.1102
answer: 673.68 = 110111011.112
Fill in the number with missing zeros on the left
Fill in the number with missing zeros on the right
let\'s do a direct translation from binary to hexadecimal like this:
000110111011.11002 = 0001 1011 1011. 1100 = 0001(=1) 1011(=B) 1011(=B). 1100(=C) = 1BB.C16
answer: 000110111011.11008 = 1BB.C16