This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
let\'s do a direct translation from binary to hexadecimal like this:
00111011001010012 = 0011 1011 0010 1001 = 0011(=3) 1011(=B) 0010(=2) 1001(=9) = 3B2916
answer: 00111011001010012 = 3B2916
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙215+0∙214+1∙213+1∙212+1∙211+0∙210+1∙29+1∙28+0∙27+0∙26+1∙25+0∙24+1∙23+0∙22+0∙21+1∙20 = 0∙32768+0∙16384+1∙8192+1∙4096+1∙2048+0∙1024+1∙512+1∙256+0∙128+0∙64+1∙32+0∙16+1∙8+0∙4+0∙2+1∙1 = 0+0+8192+4096+2048+0+512+256+0+0+32+0+8+0+0+1 = 1514510
got It: 00111011001010012 =1514510
Translate the number 1514510 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
15145 | 16 | | | |
-15136 | 946 | 16 | | |
9 | -944 | 59 | 16 | |
| 2 | -48 | 3 | |
| | B | | |
|
the result of the conversion was:
1514510 = 3B2916
answer: 00111011001010012 = 3B2916