This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
Fill in the number with missing zeros on the right
let\'s make a direct translation from binary to post-binary like this:
000000.1101002 = 000 000. 110 100 = 000(=0) 000(=0). 110(=6) 100(=4) = 00.648
the Final answer: 0000.11012 = 00.648
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙25+0∙24+0∙23+0∙22+0∙21+0∙20+1∙2-1+1∙2-2+0∙2-3+1∙2-4+0∙2-5+0∙2-6 = 0∙32+0∙16+0∙8+0∙4+0∙2+0∙1+1∙0.5+1∙0.25+0∙0.125+1∙0.0625+0∙0.03125+0∙0.015625 = 0+0+0+0+0+0+0.5+0.25+0+0.0625+0+0 = 0.812510
got It: 000000.1101002 =0.812510
Translate the number 0.812510 в octal like this:
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 8125*8 |
6 | .5*8 |
4 | .0*8 |
the result of the conversion was:
0.812510 = 0.648
the Final answer: 0000.11012 = 0.648