This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
Fill in the number with missing zeros on the right
let\'s make a direct translation from binary to post-binary like this:
011011011.1001010002 = 011 011 011. 100 101 000 = 011(=3) 011(=3) 011(=3). 100(=4) 101(=5) 000(=0) = 333.4508
answer: 11011011.100101002 = 333.4508
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙28+1∙27+1∙26+0∙25+1∙24+1∙23+0∙22+1∙21+1∙20+1∙2-1+0∙2-2+0∙2-3+1∙2-4+0∙2-5+1∙2-6+0∙2-7+0∙2-8+0∙2-9 = 0∙256+1∙128+1∙64+0∙32+1∙16+1∙8+0∙4+1∙2+1∙1+1∙0.5+0∙0.25+0∙0.125+1∙0.0625+0∙0.03125+1∙0.015625+0∙0.0078125+0∙0.00390625+0∙0.001953125 = 0+128+64+0+16+8+0+2+1+0.5+0+0+0.0625+0+0.015625+0+0+0 = 219.57812510
got It: 011011011.1001010002 =219.57812510
Translate the number 219.57812510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
219 | 8 | | |
-216 | 27 | 8 | |
3 | -24 | 3 | |
| 3 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 578125*8 |
4 | .625*8 |
5 | .0*8 |
the result of the conversion was:
219.57812510 = 333.458
answer: 11011011.100101002 = 333.458