This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s translate to decimal like this:
6∙85+5∙84+6∙83+3∙82+2∙81+1∙80 = 6∙32768+5∙4096+6∙512+3∙64+2∙8+1∙1 = 196608+20480+3072+192+16+1 = 22036910
got It: 6563218 =22036910
Translate the number 22036910 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
220369 | 16 | | | | |
-220368 | 13773 | 16 | | | |
1 | -13760 | 860 | 16 | | |
| D | -848 | 53 | 16 | |
| | C | -48 | 3 | |
| | | 5 | | |
|
the result of the conversion was:
22036910 = 35CD116
answer: 6563218 = 35CD116
now let\'s make the transfer using the decimal system.
let\'s do a direct translation from octal to binary like this:
6563218 = 6 5 6 3 2 1 = 6(=110) 5(=101) 6(=110) 3(=011) 2(=010) 1(=001) = 1101011100110100012
answer: 6563218 = 1101011100110100012
Fill in the number with missing zeros on the left
let\'s do a direct translation from binary to hexadecimal like this:
001101011100110100012 = 0011 0101 1100 1101 0001 = 0011(=3) 0101(=5) 1100(=C) 1101(=D) 0001(=1) = 35CD116
answer: 001101011100110100018 = 35CD116