This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from octal to binary like this:
6352.7458 = 6 3 5 2. 7 4 5 = 6(=110) 3(=011) 5(=101) 2(=010). 7(=111) 4(=100) 5(=101) = 110011101010.1111001012
answer: 6352.7458 = 110011101010.1111001012
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
6∙83+3∙82+5∙81+2∙80+7∙8-1+4∙8-2+5∙8-3 = 6∙512+3∙64+5∙8+2∙1+7∙0.125+4∙0.015625+5∙0.001953125 = 3072+192+40+2+0.875+0.0625+0.009765625 = 3306.94726562510
got It: 6352.7458 =3306.94726562510
Translate the number 3306.94726562510 в binary like this:
the Integer part of the number is divided by the base of the new number system:
3306 | 2 | | | | | | | | | | | |
-3306 | 1653 | 2 | | | | | | | | | | |
0 | -1652 | 826 | 2 | | | | | | | | | |
| 1 | -826 | 413 | 2 | | | | | | | | |
| | 0 | -412 | 206 | 2 | | | | | | | |
| | | 1 | -206 | 103 | 2 | | | | | | |
| | | | 0 | -102 | 51 | 2 | | | | | |
| | | | | 1 | -50 | 25 | 2 | | | | |
| | | | | | 1 | -24 | 12 | 2 | | | |
| | | | | | | 1 | -12 | 6 | 2 | | |
| | | | | | | | 0 | -6 | 3 | 2 | |
| | | | | | | | | 0 | -2 | 1 | |
| | | | | | | | | | 1 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 947265625*2 |
1 | .89453*2 |
1 | .78906*2 |
1 | .57813*2 |
1 | .15625*2 |
0 | .3125*2 |
0 | .625*2 |
1 | .25*2 |
0 | .5*2 |
1 | .0*2 |
the result of the conversion was:
3306.94726562510 = 110011101010.1111001012
answer: 6352.7458 = 110011101010.1111001012