This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
15∙162+3∙161+9∙160 = 15∙256+3∙16+9∙1 = 3840+48+9 = 389710
got It: f3916 =389710
Translate the number 389710 в octal like this:
the Integer part of the number is divided by the base of the new number system:
3897 | 8 | | | |
-3896 | 487 | 8 | | |
1 | -480 | 60 | 8 | |
| 7 | -56 | 7 | |
| | 4 | | |
|
the result of the conversion was:
389710 = 74718
answer: f3916 = 74718
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
f3916 = f 3 9 = f(=1111) 3(=0011) 9(=1001) = 1111001110012
answer: f3916 = 1111001110012
let\'s make a direct translation from binary to post-binary like this:
1111001110012 = 111 100 111 001 = 111(=7) 100(=4) 111(=7) 001(=1) = 74718
answer: f3916 = 74718