This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
Fill in the number with missing zeros on the right
let\'s make a direct translation from binary to post-binary like this:
011011011101.0110111101002 = 011 011 011 101. 011 011 110 100 = 011(=3) 011(=3) 011(=3) 101(=5). 011(=3) 011(=3) 110(=6) 100(=4) = 3335.33648
answer: 11011011101.01101111012 = 3335.33648
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙211+1∙210+1∙29+0∙28+1∙27+1∙26+0∙25+1∙24+1∙23+1∙22+0∙21+1∙20+0∙2-1+1∙2-2+1∙2-3+0∙2-4+1∙2-5+1∙2-6+1∙2-7+1∙2-8+0∙2-9+1∙2-10+0∙2-11+0∙2-12 = 0∙2048+1∙1024+1∙512+0∙256+1∙128+1∙64+0∙32+1∙16+1∙8+1∙4+0∙2+1∙1+0∙0.5+1∙0.25+1∙0.125+0∙0.0625+1∙0.03125+1∙0.015625+1∙0.0078125+1∙0.00390625+0∙0.001953125+1∙0.0009765625+0∙0.00048828125+0∙0.000244140625 = 0+1024+512+0+128+64+0+16+8+4+0+1+0+0.25+0.125+0+0.03125+0.015625+0.0078125+0.00390625+0+0.0009765625+0+0 = 1757.434570312510
got It: 011011011101.0110111101002 =1757.434570312510
Translate the number 1757.434570312510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
1757 | 8 | | | |
-1752 | 219 | 8 | | |
5 | -216 | 27 | 8 | |
| 3 | -24 | 3 | |
| | 3 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 4345703125*8 |
3 | .47656*8 |
3 | .8125*8 |
6 | .5*8 |
4 | .0*8 |
the result of the conversion was:
1757.434570312510 = 3335.33648
answer: 11011011101.01101111012 = 3335.33648