This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
0110012 = 011 001 = 011(=3) 001(=1) = 318
answer: 110012 = 318
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙25+1∙24+1∙23+0∙22+0∙21+1∙20 = 0∙32+1∙16+1∙8+0∙4+0∙2+1∙1 = 0+16+8+0+0+1 = 2510
got It: 0110012 =2510
Translate the number 2510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
25 | 8 | |
-24 | 3 | |
1 | | |
|
the result of the conversion was:
2510 = 318
answer: 110012 = 318