This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
let\'s do a direct translation from binary to hexadecimal like this:
01011011011011102 = 0101 1011 0110 1110 = 0101(=5) 1011(=B) 0110(=6) 1110(=E) = 5B6E16
answer: 01011011011011102 = 5B6E16
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙215+1∙214+0∙213+1∙212+1∙211+0∙210+1∙29+1∙28+0∙27+1∙26+1∙25+0∙24+1∙23+1∙22+1∙21+0∙20 = 0∙32768+1∙16384+0∙8192+1∙4096+1∙2048+0∙1024+1∙512+1∙256+0∙128+1∙64+1∙32+0∙16+1∙8+1∙4+1∙2+0∙1 = 0+16384+0+4096+2048+0+512+256+0+64+32+0+8+4+2+0 = 2340610
got It: 01011011011011102 =2340610
Translate the number 2340610 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
23406 | 16 | | | |
-23392 | 1462 | 16 | | |
E | -1456 | 91 | 16 | |
| 6 | -80 | 5 | |
| | B | | |
|
the result of the conversion was:
2340610 = 5B6E16
answer: 01011011011011102 = 5B6E16