This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
10∙163+13∙162+15∙161+3∙160 = 10∙4096+13∙256+15∙16+3∙1 = 40960+3328+240+3 = 4453110
got It: ADF316 =4453110
Translate the number 4453110 в octal like this:
the Integer part of the number is divided by the base of the new number system:
44531 | 8 | | | | | |
-44528 | 5566 | 8 | | | | |
3 | -5560 | 695 | 8 | | | |
| 6 | -688 | 86 | 8 | | |
| | 7 | -80 | 10 | 8 | |
| | | 6 | -8 | 1 | |
| | | | 2 | | |
|
the result of the conversion was:
4453110 = 1267638
answer: ADF316 = 1267638
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
ADF316 = A D F 3 = A(=1010) D(=1101) F(=1111) 3(=0011) = 10101101111100112
answer: ADF316 = 10101101111100112
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
0010101101111100112 = 001 010 110 111 110 011 = 001(=1) 010(=2) 110(=6) 111(=7) 110(=6) 011(=3) = 1267638
answer: ADF316 = 1267638