This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
4∙163+12∙162+10∙161+2∙160+11∙16-1+4∙16-2 = 4∙4096+12∙256+10∙16+2∙1+11∙0.0625+4∙0.00390625 = 16384+3072+160+2+0.6875+0.015625 = 19618.70312510
got It: 4CA2.B416 =19618.70312510
Translate the number 19618.70312510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
19618 | 8 | | | | |
-19616 | 2452 | 8 | | | |
2 | -2448 | 306 | 8 | | |
| 4 | -304 | 38 | 8 | |
| | 2 | -32 | 4 | |
| | | 6 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 703125*8 |
5 | .625*8 |
5 | .0*8 |
the result of the conversion was:
19618.70312510 = 46242.558
answer: 4CA2.B416 = 46242.558
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
4CA2.B416 = 4 C A 2. B 4 = 4(=0100) C(=1100) A(=1010) 2(=0010). B(=1011) 4(=0100) = 100110010100010.1011012
answer: 4CA2.B416 = 100110010100010.1011012
let\'s make a direct translation from binary to post-binary like this:
100110010100010.1011012 = 100 110 010 100 010. 101 101 = 100(=4) 110(=6) 010(=2) 100(=4) 010(=2). 101(=5) 101(=5) = 46242.558
answer: 4CA2.B416 = 46242.558