This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
10∙165+7∙164+15∙163+14∙162+10∙161+5∙160+2∙16-1+6∙16-2 = 10∙1048576+7∙65536+15∙4096+14∙256+10∙16+5∙1+2∙0.0625+6∙0.00390625 = 10485760+458752+61440+3584+160+5+0.125+0.0234375 = 11009701.148437510
got It: A7FEA5.2616 =11009701.148437510
Translate the number 11009701.148437510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
11009701 | 8 | | | | | | | |
-11009696 | 1376212 | 8 | | | | | | |
5 | -1376208 | 172026 | 8 | | | | | |
| 4 | -172024 | 21503 | 8 | | | | |
| | 2 | -21496 | 2687 | 8 | | | |
| | | 7 | -2680 | 335 | 8 | | |
| | | | 7 | -328 | 41 | 8 | |
| | | | | 7 | -40 | 5 | |
| | | | | | 1 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 1484375*8 |
1 | .1875*8 |
1 | .5*8 |
4 | .0*8 |
the result of the conversion was:
11009701.148437510 = 51777245.1148
answer: A7FEA5.2616 = 51777245.1148
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
A7FEA5.2616 = A 7 F E A 5. 2 6 = A(=1010) 7(=0111) F(=1111) E(=1110) A(=1010) 5(=0101). 2(=0010) 6(=0110) = 101001111111111010100101.00100112
answer: A7FEA5.2616 = 101001111111111010100101.00100112
Fill in the number with missing zeros on the right
let\'s make a direct translation from binary to post-binary like this:
101001111111111010100101.0010011002 = 101 001 111 111 111 010 100 101. 001 001 100 = 101(=5) 001(=1) 111(=7) 111(=7) 111(=7) 010(=2) 100(=4) 101(=5). 001(=1) 001(=1) 100(=4) = 51777245.1148
answer: A7FEA5.2616 = 51777245.1148