This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
44f6e16 = 4 4 f 6 e = 4(=0100) 4(=0100) f(=1111) 6(=0110) e(=1110) = 10001001111011011102
answer: 44f6e16 = 10001001111011011102
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
4∙164+4∙163+15∙162+6∙161+14∙160 = 4∙65536+4∙4096+15∙256+6∙16+14∙1 = 262144+16384+3840+96+14 = 28247810
got It: 44f6e16 =28247810
Translate the number 28247810 в binary like this:
the Integer part of the number is divided by the base of the new number system:
282478 | 2 | | | | | | | | | | | | | | | | | | |
-282478 | 141239 | 2 | | | | | | | | | | | | | | | | | |
0 | -141238 | 70619 | 2 | | | | | | | | | | | | | | | | |
| 1 | -70618 | 35309 | 2 | | | | | | | | | | | | | | | |
| | 1 | -35308 | 17654 | 2 | | | | | | | | | | | | | | |
| | | 1 | -17654 | 8827 | 2 | | | | | | | | | | | | | |
| | | | 0 | -8826 | 4413 | 2 | | | | | | | | | | | | |
| | | | | 1 | -4412 | 2206 | 2 | | | | | | | | | | | |
| | | | | | 1 | -2206 | 1103 | 2 | | | | | | | | | | |
| | | | | | | 0 | -1102 | 551 | 2 | | | | | | | | | |
| | | | | | | | 1 | -550 | 275 | 2 | | | | | | | | |
| | | | | | | | | 1 | -274 | 137 | 2 | | | | | | | |
| | | | | | | | | | 1 | -136 | 68 | 2 | | | | | | |
| | | | | | | | | | | 1 | -68 | 34 | 2 | | | | | |
| | | | | | | | | | | | 0 | -34 | 17 | 2 | | | | |
| | | | | | | | | | | | | 0 | -16 | 8 | 2 | | | |
| | | | | | | | | | | | | | 1 | -8 | 4 | 2 | | |
| | | | | | | | | | | | | | | 0 | -4 | 2 | 2 | |
| | | | | | | | | | | | | | | | 0 | -2 | 1 | |
| | | | | | | | | | | | | | | | | 0 | | |
|
the result of the conversion was:
28247810 = 10001001111011011102
answer: 44f6e16 = 10001001111011011102