This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s translate to decimal like this:
2∙83+4∙82+3∙81+2∙80 = 2∙512+4∙64+3∙8+2∙1 = 1024+256+24+2 = 130610
got It: 24328 =130610
Translate the number 130610 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
1306 | 16 | | |
-1296 | 81 | 16 | |
A | -80 | 5 | |
| 1 | | |
|
the result of the conversion was:
130610 = 51A16
answer: 24328 = 51A16
now let\'s make the transfer using the decimal system.
let\'s do a direct translation from octal to binary like this:
24328 = 2 4 3 2 = 2(=010) 4(=100) 3(=011) 2(=010) = 0101000110102
answer: 24328 = 101000110102
Fill in the number with missing zeros on the left
let\'s do a direct translation from binary to hexadecimal like this:
0101000110102 = 0101 0001 1010 = 0101(=5) 0001(=1) 1010(=A) = 51A16
answer: 0101000110108 = 51A16