This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
536.451216 = 5 3 6. 4 5 1 2 = 5(=0101) 3(=0011) 6(=0110). 4(=0100) 5(=0101) 1(=0001) 2(=0010) = 10100110110.0100010100010012
answer: 536.451216 = 10100110110.0100010100010012
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
5∙162+3∙161+6∙160+4∙16-1+5∙16-2+1∙16-3+2∙16-4 = 5∙256+3∙16+6∙1+4∙0.0625+5∙0.00390625+1∙0.000244140625+2∙1.52587890625E-5 = 1280+48+6+0.25+0.01953125+0.000244140625+3.0517578125E-5 = 1334.2698059082031210
got It: 536.451216 =1334.2698059082031210
Translate the number 1334.2698059082031210 в binary like this:
the Integer part of the number is divided by the base of the new number system:
1334 | 2 | | | | | | | | | | |
-1334 | 667 | 2 | | | | | | | | | |
0 | -666 | 333 | 2 | | | | | | | | |
| 1 | -332 | 166 | 2 | | | | | | | |
| | 1 | -166 | 83 | 2 | | | | | | |
| | | 0 | -82 | 41 | 2 | | | | | |
| | | | 1 | -40 | 20 | 2 | | | | |
| | | | | 1 | -20 | 10 | 2 | | | |
| | | | | | 0 | -10 | 5 | 2 | | |
| | | | | | | 0 | -4 | 2 | 2 | |
| | | | | | | | 1 | -2 | 1 | |
| | | | | | | | | 0 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 26980590820312*2 |
0 | .53961*2 |
1 | .07922*2 |
0 | .15845*2 |
0 | .31689*2 |
0 | .63379*2 |
1 | .26758*2 |
0 | .53516*2 |
1 | .07031*2 |
0 | .14062*2 |
0 | .28125*2 |
the result of the conversion was:
1334.2698059082031210 = 10100110110.01000101002
answer: 536.451216 = 10100110110.01000101002