This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
28A16 = 2 8 A = 2(=0010) 8(=1000) A(=1010) = 10100010102
answer: 28A16 = 10100010102
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
2∙162+8∙161+10∙160 = 2∙256+8∙16+10∙1 = 512+128+10 = 65010
got It: 28A16 =65010
Translate the number 65010 в binary like this:
the Integer part of the number is divided by the base of the new number system:
650 | 2 | | | | | | | | | |
-650 | 325 | 2 | | | | | | | | |
0 | -324 | 162 | 2 | | | | | | | |
| 1 | -162 | 81 | 2 | | | | | | |
| | 0 | -80 | 40 | 2 | | | | | |
| | | 1 | -40 | 20 | 2 | | | | |
| | | | 0 | -20 | 10 | 2 | | | |
| | | | | 0 | -10 | 5 | 2 | | |
| | | | | | 0 | -4 | 2 | 2 | |
| | | | | | | 1 | -2 | 1 | |
| | | | | | | | 0 | | |
|
the result of the conversion was:
65010 = 10100010102
answer: 28A16 = 10100010102