This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
B1316 = B 1 3 = B(=1011) 1(=0001) 3(=0011) = 1011000100112
answer: B1316 = 1011000100112
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
11∙162+1∙161+3∙160 = 11∙256+1∙16+3∙1 = 2816+16+3 = 283510
got It: B1316 =283510
Translate the number 283510 в binary like this:
the Integer part of the number is divided by the base of the new number system:
2835 | 2 | | | | | | | | | | | |
-2834 | 1417 | 2 | | | | | | | | | | |
1 | -1416 | 708 | 2 | | | | | | | | | |
| 1 | -708 | 354 | 2 | | | | | | | | |
| | 0 | -354 | 177 | 2 | | | | | | | |
| | | 0 | -176 | 88 | 2 | | | | | | |
| | | | 1 | -88 | 44 | 2 | | | | | |
| | | | | 0 | -44 | 22 | 2 | | | | |
| | | | | | 0 | -22 | 11 | 2 | | | |
| | | | | | | 0 | -10 | 5 | 2 | | |
| | | | | | | | 1 | -4 | 2 | 2 | |
| | | | | | | | | 1 | -2 | 1 | |
| | | | | | | | | | 0 | | |
|
the result of the conversion was:
283510 = 1011000100112
answer: B1316 = 1011000100112