This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s make a direct translation from binary to post-binary like this:
1001001012 = 100 100 101 = 100(=4) 100(=4) 101(=5) = 4458
answer: 1001001012 = 4458
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
1∙28+0∙27+0∙26+1∙25+0∙24+0∙23+1∙22+0∙21+1∙20 = 1∙256+0∙128+0∙64+1∙32+0∙16+0∙8+1∙4+0∙2+1∙1 = 256+0+0+32+0+0+4+0+1 = 29310
got It: 1001001012 =29310
Translate the number 29310 в octal like this:
the Integer part of the number is divided by the base of the new number system:
293 | 8 | | |
-288 | 36 | 8 | |
5 | -32 | 4 | |
| 4 | | |
|
the result of the conversion was:
29310 = 4458
answer: 1001001012 = 4458