This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
0010000001000112 = 001 000 000 100 011 = 001(=1) 000(=0) 000(=0) 100(=4) 011(=3) = 100438
answer: 10000001000112 = 100438
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙214+0∙213+1∙212+0∙211+0∙210+0∙29+0∙28+0∙27+0∙26+1∙25+0∙24+0∙23+0∙22+1∙21+1∙20 = 0∙16384+0∙8192+1∙4096+0∙2048+0∙1024+0∙512+0∙256+0∙128+0∙64+1∙32+0∙16+0∙8+0∙4+1∙2+1∙1 = 0+0+4096+0+0+0+0+0+0+32+0+0+0+2+1 = 413110
got It: 0010000001000112 =413110
Translate the number 413110 в octal like this:
the Integer part of the number is divided by the base of the new number system:
4131 | 8 | | | | |
-4128 | 516 | 8 | | | |
3 | -512 | 64 | 8 | | |
| 4 | -64 | 8 | 8 | |
| | 0 | -8 | 1 | |
| | | 0 | | |
|
the result of the conversion was:
413110 = 100438
answer: 10000001000112 = 100438