This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
7∙161+7∙160+1∙16-1+3∙16-2 = 7∙16+7∙1+1∙0.0625+3∙0.00390625 = 112+7+0.0625+0.01171875 = 119.0742187510
got It: 77.1316 =119.0742187510
Translate the number 119.0742187510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
119 | 8 | | |
-112 | 14 | 8 | |
7 | -8 | 1 | |
| 6 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 07421875*8 |
0 | .59375*8 |
4 | .75*8 |
6 | .0*8 |
the result of the conversion was:
119.0742187510 = 167.0468
answer: 77.1316 = 167.0468
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
77.1316 = 7 7. 1 3 = 7(=0111) 7(=0111). 1(=0001) 3(=0011) = 1110111.000100112
answer: 77.1316 = 1110111.000100112
Fill in the number with missing zeros on the left
Fill in the number with missing zeros on the right
let\'s make a direct translation from binary to post-binary like this:
001110111.0001001102 = 001 110 111. 000 100 110 = 001(=1) 110(=6) 111(=7). 000(=0) 100(=4) 110(=6) = 167.0468
answer: 77.1316 = 167.0468