This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
2∙162+13∙161+3∙160+5∙16-1 = 2∙256+13∙16+3∙1+5∙0.0625 = 512+208+3+0.3125 = 723.312510
got It: 2D3.516 =723.312510
Translate the number 723.312510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
723 | 8 | | | |
-720 | 90 | 8 | | |
3 | -88 | 11 | 8 | |
| 2 | -8 | 1 | |
| | 3 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 3125*8 |
2 | .5*8 |
4 | .0*8 |
the result of the conversion was:
723.312510 = 1323.248
answer: 2D3.516 = 1323.248
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
2D3.516 = 2 D 3. 5 = 2(=0010) D(=1101) 3(=0011). 5(=0101) = 1011010011.01012
answer: 2D3.516 = 1011010011.01012
Fill in the number with missing zeros on the left
Fill in the number with missing zeros on the right
let\'s make a direct translation from binary to post-binary like this:
001011010011.0101002 = 001 011 010 011. 010 100 = 001(=1) 011(=3) 010(=2) 011(=3). 010(=2) 100(=4) = 1323.248
answer: 2D3.516 = 1323.248