This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
445916 = 4 4 5 9 = 4(=0100) 4(=0100) 5(=0101) 9(=1001) = 1000100010110012
answer: 445916 = 1000100010110012
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
4∙163+4∙162+5∙161+9∙160 = 4∙4096+4∙256+5∙16+9∙1 = 16384+1024+80+9 = 1749710
got It: 445916 =1749710
Translate the number 1749710 в binary like this:
the Integer part of the number is divided by the base of the new number system:
17497 | 2 | | | | | | | | | | | | | | |
-17496 | 8748 | 2 | | | | | | | | | | | | | |
1 | -8748 | 4374 | 2 | | | | | | | | | | | | |
| 0 | -4374 | 2187 | 2 | | | | | | | | | | | |
| | 0 | -2186 | 1093 | 2 | | | | | | | | | | |
| | | 1 | -1092 | 546 | 2 | | | | | | | | | |
| | | | 1 | -546 | 273 | 2 | | | | | | | | |
| | | | | 0 | -272 | 136 | 2 | | | | | | | |
| | | | | | 1 | -136 | 68 | 2 | | | | | | |
| | | | | | | 0 | -68 | 34 | 2 | | | | | |
| | | | | | | | 0 | -34 | 17 | 2 | | | | |
| | | | | | | | | 0 | -16 | 8 | 2 | | | |
| | | | | | | | | | 1 | -8 | 4 | 2 | | |
| | | | | | | | | | | 0 | -4 | 2 | 2 | |
| | | | | | | | | | | | 0 | -2 | 1 | |
| | | | | | | | | | | | | 0 | | |
|
the result of the conversion was:
1749710 = 1000100010110012
answer: 445916 = 1000100010110012