This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s translate to decimal like this:
5∙82+6∙81+7∙80 = 5∙64+6∙8+7∙1 = 320+48+7 = 37510
got It: 5678 =37510
Translate the number 37510 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
375 | 16 | | |
-368 | 23 | 16 | |
7 | -16 | 1 | |
| 7 | | |
|
the result of the conversion was:
37510 = 17716
answer: 5678 = 17716
now let\'s make the transfer using the decimal system.
let\'s do a direct translation from octal to binary like this:
5678 = 5 6 7 = 5(=101) 6(=110) 7(=111) = 1011101112
answer: 5678 = 1011101112
Fill in the number with missing zeros on the left
let\'s do a direct translation from binary to hexadecimal like this:
0001011101112 = 0001 0111 0111 = 0001(=1) 0111(=7) 0111(=7) = 17716
answer: 0001011101118 = 17716