This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
4∙161+7∙160+5∙16-1+2∙16-2 = 4∙16+7∙1+5∙0.0625+2∙0.00390625 = 64+7+0.3125+0.0078125 = 71.320312510
got It: 47.5216 =71.320312510
Translate the number 71.320312510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
71 | 8 | | |
-64 | 8 | 8 | |
7 | -8 | 1 | |
| 0 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 3203125*8 |
2 | .5625*8 |
4 | .5*8 |
4 | .0*8 |
the result of the conversion was:
71.320312510 = 107.2448
answer: 47.5216 = 107.2448
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
47.5216 = 4 7. 5 2 = 4(=0100) 7(=0111). 5(=0101) 2(=0010) = 1000111.01010012
answer: 47.5216 = 1000111.01010012
Fill in the number with missing zeros on the left
Fill in the number with missing zeros on the right
let\'s make a direct translation from binary to post-binary like this:
001000111.0101001002 = 001 000 111. 010 100 100 = 001(=1) 000(=0) 111(=7). 010(=2) 100(=4) 100(=4) = 107.2448
answer: 47.5216 = 107.2448