This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
3∙160+14∙16-1 = 3∙1+14∙0.0625 = 3+0.875 = 3.87510
got It: 3.e16 =3.87510
Translate the number 3.87510 в octal like this:
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 875*8 |
7 | .0*8 |
the result of the conversion was:
3.87510 = 3.78
answer: 3.e16 = 3.78
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
3.e16 = 3. e = 3(=0011). e(=1110) = 11.1112
answer: 3.e16 = 11.1112
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
011.1112 = 011. 111 = 011(=3). 111(=7) = 3.78
answer: 3.e16 = 3.78