This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
0∙167+1∙166+14∙165+0∙164+0∙163+0∙162+0∙161+0∙160 = 0∙268435456+1∙16777216+14∙1048576+0∙65536+0∙4096+0∙256+0∙16+0∙1 = 0+16777216+14680064+0+0+0+0+0 = 3145728010
got It: 01e0000016 =3145728010
Translate the number 3145728010 в octal like this:
the Integer part of the number is divided by the base of the new number system:
31457280 | 8 | | | | | | | | |
-31457280 | 3932160 | 8 | | | | | | | |
0 | -3932160 | 491520 | 8 | | | | | | |
| 0 | -491520 | 61440 | 8 | | | | | |
| | 0 | -61440 | 7680 | 8 | | | | |
| | | 0 | -7680 | 960 | 8 | | | |
| | | | 0 | -960 | 120 | 8 | | |
| | | | | 0 | -120 | 15 | 8 | |
| | | | | | 0 | -8 | 1 | |
| | | | | | | 7 | | |
|
the result of the conversion was:
3145728010 = 1700000008
answer: 01e0000016 = 1700000008
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
01e0000016 = 0 1 e 0 0 0 0 0 = 0(=0000) 1(=0001) e(=1110) 0(=0000) 0(=0000) 0(=0000) 0(=0000) 0(=0000) = 11110000000000000000000002
answer: 01e0000016 = 11110000000000000000000002
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
0011110000000000000000000002 = 001 111 000 000 000 000 000 000 000 = 001(=1) 111(=7) 000(=0) 000(=0) 000(=0) 000(=0) 000(=0) 000(=0) 000(=0) = 1700000008
answer: 01e0000016 = 1700000008