This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
2AC5D16 = 2 A C 5 D = 2(=0010) A(=1010) C(=1100) 5(=0101) D(=1101) = 1010101100010111012
answer: 2AC5D16 = 1010101100010111012
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
2∙164+10∙163+12∙162+5∙161+13∙160 = 2∙65536+10∙4096+12∙256+5∙16+13∙1 = 131072+40960+3072+80+13 = 17519710
got It: 2AC5D16 =17519710
Translate the number 17519710 в binary like this:
the Integer part of the number is divided by the base of the new number system:
175197 | 2 | | | | | | | | | | | | | | | | | |
-175196 | 87598 | 2 | | | | | | | | | | | | | | | | |
1 | -87598 | 43799 | 2 | | | | | | | | | | | | | | | |
| 0 | -43798 | 21899 | 2 | | | | | | | | | | | | | | |
| | 1 | -21898 | 10949 | 2 | | | | | | | | | | | | | |
| | | 1 | -10948 | 5474 | 2 | | | | | | | | | | | | |
| | | | 1 | -5474 | 2737 | 2 | | | | | | | | | | | |
| | | | | 0 | -2736 | 1368 | 2 | | | | | | | | | | |
| | | | | | 1 | -1368 | 684 | 2 | | | | | | | | | |
| | | | | | | 0 | -684 | 342 | 2 | | | | | | | | |
| | | | | | | | 0 | -342 | 171 | 2 | | | | | | | |
| | | | | | | | | 0 | -170 | 85 | 2 | | | | | | |
| | | | | | | | | | 1 | -84 | 42 | 2 | | | | | |
| | | | | | | | | | | 1 | -42 | 21 | 2 | | | | |
| | | | | | | | | | | | 0 | -20 | 10 | 2 | | | |
| | | | | | | | | | | | | 1 | -10 | 5 | 2 | | |
| | | | | | | | | | | | | | 0 | -4 | 2 | 2 | |
| | | | | | | | | | | | | | | 1 | -2 | 1 | |
| | | | | | | | | | | | | | | | 0 | | |
|
the result of the conversion was:
17519710 = 1010101100010111012
answer: 2AC5D16 = 1010101100010111012