This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
1A9C2F16 = 1 A 9 C 2 F = 1(=0001) A(=1010) 9(=1001) C(=1100) 2(=0010) F(=1111) = 1101010011100001011112
answer: 1A9C2F16 = 1101010011100001011112
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
1∙165+10∙164+9∙163+12∙162+2∙161+15∙160 = 1∙1048576+10∙65536+9∙4096+12∙256+2∙16+15∙1 = 1048576+655360+36864+3072+32+15 = 174391910
got It: 1A9C2F16 =174391910
Translate the number 174391910 в binary like this:
the Integer part of the number is divided by the base of the new number system:
1743919 | 2 | | | | | | | | | | | | | | | | | | | | |
-1743918 | 871959 | 2 | | | | | | | | | | | | | | | | | | | |
1 | -871958 | 435979 | 2 | | | | | | | | | | | | | | | | | | |
| 1 | -435978 | 217989 | 2 | | | | | | | | | | | | | | | | | |
| | 1 | -217988 | 108994 | 2 | | | | | | | | | | | | | | | | |
| | | 1 | -108994 | 54497 | 2 | | | | | | | | | | | | | | | |
| | | | 0 | -54496 | 27248 | 2 | | | | | | | | | | | | | | |
| | | | | 1 | -27248 | 13624 | 2 | | | | | | | | | | | | | |
| | | | | | 0 | -13624 | 6812 | 2 | | | | | | | | | | | | |
| | | | | | | 0 | -6812 | 3406 | 2 | | | | | | | | | | | |
| | | | | | | | 0 | -3406 | 1703 | 2 | | | | | | | | | | |
| | | | | | | | | 0 | -1702 | 851 | 2 | | | | | | | | | |
| | | | | | | | | | 1 | -850 | 425 | 2 | | | | | | | | |
| | | | | | | | | | | 1 | -424 | 212 | 2 | | | | | | | |
| | | | | | | | | | | | 1 | -212 | 106 | 2 | | | | | | |
| | | | | | | | | | | | | 0 | -106 | 53 | 2 | | | | | |
| | | | | | | | | | | | | | 0 | -52 | 26 | 2 | | | | |
| | | | | | | | | | | | | | | 1 | -26 | 13 | 2 | | | |
| | | | | | | | | | | | | | | | 0 | -12 | 6 | 2 | | |
| | | | | | | | | | | | | | | | | 1 | -6 | 3 | 2 | |
| | | | | | | | | | | | | | | | | | 0 | -2 | 1 | |
| | | | | | | | | | | | | | | | | | | 1 | | |
|
the result of the conversion was:
174391910 = 1101010011100001011112
answer: 1A9C2F16 = 1101010011100001011112