This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
679F16 = 6 7 9 F = 6(=0110) 7(=0111) 9(=1001) F(=1111) = 1100111100111112
answer: 679F16 = 1100111100111112
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
6∙163+7∙162+9∙161+15∙160 = 6∙4096+7∙256+9∙16+15∙1 = 24576+1792+144+15 = 2652710
got It: 679F16 =2652710
Translate the number 2652710 в binary like this:
the Integer part of the number is divided by the base of the new number system:
26527 | 2 | | | | | | | | | | | | | | |
-26526 | 13263 | 2 | | | | | | | | | | | | | |
1 | -13262 | 6631 | 2 | | | | | | | | | | | | |
| 1 | -6630 | 3315 | 2 | | | | | | | | | | | |
| | 1 | -3314 | 1657 | 2 | | | | | | | | | | |
| | | 1 | -1656 | 828 | 2 | | | | | | | | | |
| | | | 1 | -828 | 414 | 2 | | | | | | | | |
| | | | | 0 | -414 | 207 | 2 | | | | | | | |
| | | | | | 0 | -206 | 103 | 2 | | | | | | |
| | | | | | | 1 | -102 | 51 | 2 | | | | | |
| | | | | | | | 1 | -50 | 25 | 2 | | | | |
| | | | | | | | | 1 | -24 | 12 | 2 | | | |
| | | | | | | | | | 1 | -12 | 6 | 2 | | |
| | | | | | | | | | | 0 | -6 | 3 | 2 | |
| | | | | | | | | | | | 0 | -2 | 1 | |
| | | | | | | | | | | | | 1 | | |
|
the result of the conversion was:
2652710 = 1100111100111112
answer: 679F16 = 1100111100111112