This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
8ade16 = 8 a d e = 8(=1000) a(=1010) d(=1101) e(=1110) = 10001010110111102
answer: 8ade16 = 10001010110111102
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
8∙163+10∙162+13∙161+14∙160 = 8∙4096+10∙256+13∙16+14∙1 = 32768+2560+208+14 = 3555010
got It: 8ade16 =3555010
Translate the number 3555010 в binary like this:
the Integer part of the number is divided by the base of the new number system:
35550 | 2 | | | | | | | | | | | | | | | |
-35550 | 17775 | 2 | | | | | | | | | | | | | | |
0 | -17774 | 8887 | 2 | | | | | | | | | | | | | |
| 1 | -8886 | 4443 | 2 | | | | | | | | | | | | |
| | 1 | -4442 | 2221 | 2 | | | | | | | | | | | |
| | | 1 | -2220 | 1110 | 2 | | | | | | | | | | |
| | | | 1 | -1110 | 555 | 2 | | | | | | | | | |
| | | | | 0 | -554 | 277 | 2 | | | | | | | | |
| | | | | | 1 | -276 | 138 | 2 | | | | | | | |
| | | | | | | 1 | -138 | 69 | 2 | | | | | | |
| | | | | | | | 0 | -68 | 34 | 2 | | | | | |
| | | | | | | | | 1 | -34 | 17 | 2 | | | | |
| | | | | | | | | | 0 | -16 | 8 | 2 | | | |
| | | | | | | | | | | 1 | -8 | 4 | 2 | | |
| | | | | | | | | | | | 0 | -4 | 2 | 2 | |
| | | | | | | | | | | | | 0 | -2 | 1 | |
| | | | | | | | | | | | | | 0 | | |
|
the result of the conversion was:
3555010 = 10001010110111102
answer: 8ade16 = 10001010110111102