This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from octal to binary like this:
2028 = 2 0 2 = 2(=010) 0(=000) 2(=010) = 0100000102
answer: 2028 = 100000102
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
2∙82+0∙81+2∙80 = 2∙64+0∙8+2∙1 = 128+0+2 = 13010
got It: 2028 =13010
Translate the number 13010 в binary like this:
the Integer part of the number is divided by the base of the new number system:
130 | 2 | | | | | | | |
-130 | 65 | 2 | | | | | | |
0 | -64 | 32 | 2 | | | | | |
| 1 | -32 | 16 | 2 | | | | |
| | 0 | -16 | 8 | 2 | | | |
| | | 0 | -8 | 4 | 2 | | |
| | | | 0 | -4 | 2 | 2 | |
| | | | | 0 | -2 | 1 | |
| | | | | | 0 | | |
|
the result of the conversion was:
13010 = 100000102
answer: 2028 = 100000102