This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from octal to binary like this:
6678 = 6 6 7 = 6(=110) 6(=110) 7(=111) = 1101101112
answer: 6678 = 1101101112
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
6∙82+6∙81+7∙80 = 6∙64+6∙8+7∙1 = 384+48+7 = 43910
got It: 6678 =43910
Translate the number 43910 в binary like this:
the Integer part of the number is divided by the base of the new number system:
439 | 2 | | | | | | | | |
-438 | 219 | 2 | | | | | | | |
1 | -218 | 109 | 2 | | | | | | |
| 1 | -108 | 54 | 2 | | | | | |
| | 1 | -54 | 27 | 2 | | | | |
| | | 0 | -26 | 13 | 2 | | | |
| | | | 1 | -12 | 6 | 2 | | |
| | | | | 1 | -6 | 3 | 2 | |
| | | | | | 0 | -2 | 1 | |
| | | | | | | 1 | | |
|
the result of the conversion was:
43910 = 1101101112
answer: 6678 = 1101101112