This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
10∙162+11∙161+5∙160 = 10∙256+11∙16+5∙1 = 2560+176+5 = 274110
got It: AB516 =274110
Translate the number 274110 в octal like this:
the Integer part of the number is divided by the base of the new number system:
2741 | 8 | | | |
-2736 | 342 | 8 | | |
5 | -336 | 42 | 8 | |
| 6 | -40 | 5 | |
| | 2 | | |
|
the result of the conversion was:
274110 = 52658
answer: AB516 = 52658
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
AB516 = A B 5 = A(=1010) B(=1011) 5(=0101) = 1010101101012
answer: AB516 = 1010101101012
let\'s make a direct translation from binary to post-binary like this:
1010101101012 = 101 010 110 101 = 101(=5) 010(=2) 110(=6) 101(=5) = 52658
answer: AB516 = 52658