This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
Fill in the number with missing zeros on the right
let\'s make a direct translation from binary to post-binary like this:
010111011.1111002 = 010 111 011. 111 100 = 010(=2) 111(=7) 011(=3). 111(=7) 100(=4) = 273.748
answer: 10111011.11112 = 273.748
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙28+1∙27+0∙26+1∙25+1∙24+1∙23+0∙22+1∙21+1∙20+1∙2-1+1∙2-2+1∙2-3+1∙2-4+0∙2-5+0∙2-6 = 0∙256+1∙128+0∙64+1∙32+1∙16+1∙8+0∙4+1∙2+1∙1+1∙0.5+1∙0.25+1∙0.125+1∙0.0625+0∙0.03125+0∙0.015625 = 0+128+0+32+16+8+0+2+1+0.5+0.25+0.125+0.0625+0+0 = 187.937510
got It: 010111011.1111002 =187.937510
Translate the number 187.937510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
187 | 8 | | |
-184 | 23 | 8 | |
3 | -16 | 2 | |
| 7 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 9375*8 |
7 | .5*8 |
4 | .0*8 |
the result of the conversion was:
187.937510 = 273.748
answer: 10111011.11112 = 273.748