This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
Fill in the number with missing zeros on the right
let\'s make a direct translation from binary to post-binary like this:
011101.1101002 = 011 101. 110 100 = 011(=3) 101(=5). 110(=6) 100(=4) = 35.648
answer: 11101.11012 = 35.648
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙25+1∙24+1∙23+1∙22+0∙21+1∙20+1∙2-1+1∙2-2+0∙2-3+1∙2-4+0∙2-5+0∙2-6 = 0∙32+1∙16+1∙8+1∙4+0∙2+1∙1+1∙0.5+1∙0.25+0∙0.125+1∙0.0625+0∙0.03125+0∙0.015625 = 0+16+8+4+0+1+0.5+0.25+0+0.0625+0+0 = 29.812510
got It: 011101.1101002 =29.812510
Translate the number 29.812510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
29 | 8 | |
-24 | 3 | |
5 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 8125*8 |
6 | .5*8 |
4 | .0*8 |
the result of the conversion was:
29.812510 = 35.648
answer: 11101.11012 = 35.648