This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s translate to decimal like this:
2∙80+5∙8-1+5∙8-2+3∙8-3+4∙8-4 = 2∙1+5∙0.125+5∙0.015625+3∙0.001953125+4∙0.000244140625 = 2+0.625+0.078125+0.005859375+0.0009765625 = 2.709960937510
got It: 2.55348 =2.709960937510
Translate the number 2.709960937510 в hexadecimal like this:
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 7099609375*16 |
B | .35938*16 |
5 | .75*16 |
C | .0*16 |
the result of the conversion was:
2.709960937510 = 2.B5C16
answer: 2.55348 = 2.B5C16
now let\'s make the transfer using the decimal system.
let\'s do a direct translation from octal to binary like this:
2.55348 = 2. 5 5 3 4 = 2(=010). 5(=101) 5(=101) 3(=011) 4(=100) = 010.1011010111002
answer: 2.55348 = 10.10110101112
Fill in the number with missing zeros on the left
Fill in the number with missing zeros on the right
let\'s do a direct translation from binary to hexadecimal like this:
0010.1011010111002 = 0010. 1011 0101 1100 = 0010(=2). 1011(=B) 0101(=5) 1100(=C) = 2.B5C16
answer: 0010.1011010111008 = 2.B5C16