This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
4∙162+6∙161+2∙160 = 4∙256+6∙16+2∙1 = 1024+96+2 = 112210
got It: 46216 =112210
Translate the number 112210 в octal like this:
the Integer part of the number is divided by the base of the new number system:
1122 | 8 | | | |
-1120 | 140 | 8 | | |
2 | -136 | 17 | 8 | |
| 4 | -16 | 2 | |
| | 1 | | |
|
the result of the conversion was:
112210 = 21428
answer: 46216 = 21428
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
46216 = 4 6 2 = 4(=0100) 6(=0110) 2(=0010) = 100011000102
answer: 46216 = 100011000102
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
0100011000102 = 010 001 100 010 = 010(=2) 001(=1) 100(=4) 010(=2) = 21428
answer: 46216 = 21428