This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
F01816 = F 0 1 8 = F(=1111) 0(=0000) 1(=0001) 8(=1000) = 11110000000110002
answer: F01816 = 11110000000110002
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
15∙163+0∙162+1∙161+8∙160 = 15∙4096+0∙256+1∙16+8∙1 = 61440+0+16+8 = 6146410
got It: F01816 =6146410
Translate the number 6146410 в binary like this:
the Integer part of the number is divided by the base of the new number system:
61464 | 2 | | | | | | | | | | | | | | | |
-61464 | 30732 | 2 | | | | | | | | | | | | | | |
0 | -30732 | 15366 | 2 | | | | | | | | | | | | | |
| 0 | -15366 | 7683 | 2 | | | | | | | | | | | | |
| | 0 | -7682 | 3841 | 2 | | | | | | | | | | | |
| | | 1 | -3840 | 1920 | 2 | | | | | | | | | | |
| | | | 1 | -1920 | 960 | 2 | | | | | | | | | |
| | | | | 0 | -960 | 480 | 2 | | | | | | | | |
| | | | | | 0 | -480 | 240 | 2 | | | | | | | |
| | | | | | | 0 | -240 | 120 | 2 | | | | | | |
| | | | | | | | 0 | -120 | 60 | 2 | | | | | |
| | | | | | | | | 0 | -60 | 30 | 2 | | | | |
| | | | | | | | | | 0 | -30 | 15 | 2 | | | |
| | | | | | | | | | | 0 | -14 | 7 | 2 | | |
| | | | | | | | | | | | 1 | -6 | 3 | 2 | |
| | | | | | | | | | | | | 1 | -2 | 1 | |
| | | | | | | | | | | | | | 1 | | |
|
the result of the conversion was:
6146410 = 11110000000110002
answer: F01816 = 11110000000110002