This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from octal to binary like this:
67058 = 6 7 0 5 = 6(=110) 7(=111) 0(=000) 5(=101) = 1101110001012
answer: 67058 = 1101110001012
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
6∙83+7∙82+0∙81+5∙80 = 6∙512+7∙64+0∙8+5∙1 = 3072+448+0+5 = 352510
got It: 67058 =352510
Translate the number 352510 в binary like this:
the Integer part of the number is divided by the base of the new number system:
3525 | 2 | | | | | | | | | | | |
-3524 | 1762 | 2 | | | | | | | | | | |
1 | -1762 | 881 | 2 | | | | | | | | | |
| 0 | -880 | 440 | 2 | | | | | | | | |
| | 1 | -440 | 220 | 2 | | | | | | | |
| | | 0 | -220 | 110 | 2 | | | | | | |
| | | | 0 | -110 | 55 | 2 | | | | | |
| | | | | 0 | -54 | 27 | 2 | | | | |
| | | | | | 1 | -26 | 13 | 2 | | | |
| | | | | | | 1 | -12 | 6 | 2 | | |
| | | | | | | | 1 | -6 | 3 | 2 | |
| | | | | | | | | 0 | -2 | 1 | |
| | | | | | | | | | 1 | | |
|
the result of the conversion was:
352510 = 1101110001012
answer: 67058 = 1101110001012