This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
F4C16 = F 4 C = F(=1111) 4(=0100) C(=1100) = 1111010011002
answer: F4C16 = 1111010011002
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
15∙162+4∙161+12∙160 = 15∙256+4∙16+12∙1 = 3840+64+12 = 391610
got It: F4C16 =391610
Translate the number 391610 в binary like this:
the Integer part of the number is divided by the base of the new number system:
3916 | 2 | | | | | | | | | | | |
-3916 | 1958 | 2 | | | | | | | | | | |
0 | -1958 | 979 | 2 | | | | | | | | | |
| 0 | -978 | 489 | 2 | | | | | | | | |
| | 1 | -488 | 244 | 2 | | | | | | | |
| | | 1 | -244 | 122 | 2 | | | | | | |
| | | | 0 | -122 | 61 | 2 | | | | | |
| | | | | 0 | -60 | 30 | 2 | | | | |
| | | | | | 1 | -30 | 15 | 2 | | | |
| | | | | | | 0 | -14 | 7 | 2 | | |
| | | | | | | | 1 | -6 | 3 | 2 | |
| | | | | | | | | 1 | -2 | 1 | |
| | | | | | | | | | 1 | | |
|
the result of the conversion was:
391610 = 1111010011002
answer: F4C16 = 1111010011002