This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
15∙163+14∙162+8∙161+0∙160 = 15∙4096+14∙256+8∙16+0∙1 = 61440+3584+128+0 = 6515210
got It: fe8016 =6515210
Translate the number 6515210 в octal like this:
the Integer part of the number is divided by the base of the new number system:
65152 | 8 | | | | | |
-65152 | 8144 | 8 | | | | |
0 | -8144 | 1018 | 8 | | | |
| 0 | -1016 | 127 | 8 | | |
| | 2 | -120 | 15 | 8 | |
| | | 7 | -8 | 1 | |
| | | | 7 | | |
|
the result of the conversion was:
6515210 = 1772008
answer: fe8016 = 1772008
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
fe8016 = f e 8 0 = f(=1111) e(=1110) 8(=1000) 0(=0000) = 11111110100000002
answer: fe8016 = 11111110100000002
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
0011111110100000002 = 001 111 111 010 000 000 = 001(=1) 111(=7) 111(=7) 010(=2) 000(=0) 000(=0) = 1772008
answer: fe8016 = 1772008