This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s translate to decimal like this:
7∙82+1∙81+5∙80+2∙8-1 = 7∙64+1∙8+5∙1+2∙0.125 = 448+8+5+0.25 = 461.2510
got It: 715.28 =461.2510
Translate the number 461.2510 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
461 | 16 | | |
-448 | 28 | 16 | |
D | -16 | 1 | |
| C | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 25*16 |
4 | .0*16 |
the result of the conversion was:
461.2510 = 1CD.416
answer: 715.28 = 1CD.416
now let\'s make the transfer using the decimal system.
let\'s do a direct translation from octal to binary like this:
715.28 = 7 1 5. 2 = 7(=111) 1(=001) 5(=101). 2(=010) = 111001101.0102
answer: 715.28 = 111001101.012
Fill in the number with missing zeros on the left
Fill in the number with missing zeros on the right
let\'s do a direct translation from binary to hexadecimal like this:
000111001101.01002 = 0001 1100 1101. 0100 = 0001(=1) 1100(=C) 1101(=D). 0100(=4) = 1CD.416
answer: 000111001101.01008 = 1CD.416