This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
A0A16 = A 0 A = A(=1010) 0(=0000) A(=1010) = 1010000010102
answer: A0A16 = 1010000010102
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
10∙162+0∙161+10∙160 = 10∙256+0∙16+10∙1 = 2560+0+10 = 257010
got It: A0A16 =257010
Translate the number 257010 в binary like this:
the Integer part of the number is divided by the base of the new number system:
2570 | 2 | | | | | | | | | | | |
-2570 | 1285 | 2 | | | | | | | | | | |
0 | -1284 | 642 | 2 | | | | | | | | | |
| 1 | -642 | 321 | 2 | | | | | | | | |
| | 0 | -320 | 160 | 2 | | | | | | | |
| | | 1 | -160 | 80 | 2 | | | | | | |
| | | | 0 | -80 | 40 | 2 | | | | | |
| | | | | 0 | -40 | 20 | 2 | | | | |
| | | | | | 0 | -20 | 10 | 2 | | | |
| | | | | | | 0 | -10 | 5 | 2 | | |
| | | | | | | | 0 | -4 | 2 | 2 | |
| | | | | | | | | 1 | -2 | 1 | |
| | | | | | | | | | 0 | | |
|
the result of the conversion was:
257010 = 1010000010102
answer: A0A16 = 1010000010102