This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s translate to decimal like this:
1∙83+2∙82+4∙81+5∙80 = 1∙512+2∙64+4∙8+5∙1 = 512+128+32+5 = 67710
got It: 12458 =67710
Translate the number 67710 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
677 | 16 | | |
-672 | 42 | 16 | |
5 | -32 | 2 | |
| A | | |
|
the result of the conversion was:
67710 = 2A516
answer: 12458 = 2A516
now let\'s make the transfer using the decimal system.
let\'s do a direct translation from octal to binary like this:
12458 = 1 2 4 5 = 1(=001) 2(=010) 4(=100) 5(=101) = 0010101001012
answer: 12458 = 10101001012
Fill in the number with missing zeros on the left
let\'s do a direct translation from binary to hexadecimal like this:
0010101001012 = 0010 1010 0101 = 0010(=2) 1010(=A) 0101(=5) = 2A516
answer: 0010101001018 = 2A516